How many users can I support with this structure?

Re: How many users can I support with this structure?

by Sylvio Runge -
Number of replies: 0
ca. (!!!)
2G - 500M (Windows internally/cache) = 1,5G
1,5G/(about 35Mbyte) => max. 50 simultaneous user (active)

It is depency, which simultaneous the users straight make and which
moodle-version and Web-server.

s.