Re: How many users can I support with this structure? by Sylvio Runge - Monday, 2 July 2007, 7:59 PM Number of replies: 0 ca. (!!!)2G - 500M (Windows internally/cache) = 1,5G1,5G/(about 35Mbyte) => max. 50 simultaneous user (active)It is depency, which simultaneous the users straight make and whichmoodle-version and Web-server.s. Average of ratings: - Permalink Show parent Reply