$course$/000 Experimental//debugging questions/EXPORT4.5030 t=sqrt(2d/g) formulaStarting from "Galileo's formula" for how far something will fall, \[ d=(1/2)*gt^2\] solve the formula for t, the time it takes to fall a certain distance d.

Note: Moodle is fussy. If you wanted to tell Moodle the answer is \(\sqrt\frac{5*g}{d}\) you would type in "sqrt(5*g/d)". (That's not the answer, of course.)

t=[[input:ans1]]

[[validation:ans1]]

]]>1.00000000.10000000[[feedback:prt1]]10Correct answer, well done.Your answer is partially correct.Incorrect answer.none1icos-1ans1algebraicsqrt(2*d/g)150100111prt11.000000010AlgEquivans1sqrt(2*d/g)0=1.0000000-1prt1-1-T(2*d/g)^(1/2) ]]>=0.0000000-1prt1-1-F