I have an electrical questions that I am trying to code as a calculated quiz question:
A {R} Ω resistor has a rated power dissipation of {P} W. What is the maximum current (in A) that the resistor can pass while not exceeding its rated power?
The formula is pow({P}/{R}, 0.5), which works fine.
However, what I want to do is to select {P} and {R} from two independent sets with predefined values.
For example, I would like the resistance set to be this:
{R} = [1, 2, 5, 10, 20, 50, 100, 200, 500]
And the power set to be this:
{P} = [0.25, 0.5, 1, 5, 10, 25, 50, 100, 250, 500]
And have the sets selected independently. In other words, there should be 90 possible questions.
Is it possible to do this easily? It seems that you cannot edit the sets of values independently, and have to enter fixed values pair by pair.
I cannot determine the version of Moodle our institution is using.
Thanks
Bart
Selecting independent subsets of Question Calculation variables
by bjem Milne -
Number of replies: 4
In reply to bjem Milne
Re: Selecting independent subsets of Question Calculation variables
by Tim Hunt -
Not easy to do this with the standard calculated question type. Nor with the add-on 'variable numeric sets'.
(Well, it is possible, but you need to create all 90 pairs of values as separate datasets.)
The alternative is to just generate 10 or so pairs of values yourself. Given the formula, any case where R is equal to P is easier because the division is just 1, as are cases where P/R is 1, 25 or 100, because then the sqrt is obvious. So if you do 'randomly' select some pairs yourself, you can ensure that they are all about equally difficult.
It is possible to do exactly what you want with add-on question types STACK, and I assume with Formulas, since they give you much more control but obviously they require installing extra plugins.
(Well, it is possible, but you need to create all 90 pairs of values as separate datasets.)
The alternative is to just generate 10 or so pairs of values yourself. Given the formula, any case where R is equal to P is easier because the division is just 1, as are cases where P/R is 1, 25 or 100, because then the sqrt is obvious. So if you do 'randomly' select some pairs yourself, you can ensure that they are all about equally difficult.
It is possible to do exactly what you want with add-on question types STACK, and I assume with Formulas, since they give you much more control but obviously they require installing extra plugins.
In reply to Tim Hunt
Re: Selecting independent subsets of Question Calculation variables
by AL Rachels -
Definitely can be done with Formulas question type.
In reply to AL Rachels
Re: Selecting independent subsets of Question Calculation variables
by Dominique Bauer -
and most easily!
Random variables
R = {1,2,5,10,20,50,100,200,500};
P = {0.25,0.5,1,5,10,25,50,100,250,500};
Global variables
I = pow(P/R,0.5);
Answer
I
Unit
A
Part's text
{_0}{_u}
In reply to Dominique Bauer
Re: Selecting independent subsets of Question Calculation variables
by bjem Milne -
Thank you all. I am in the process of getting this question type installed.